$$ \vec H = \left(\! \ffd{1}{4 \pi} \!\right) \int\! \ffd{dq(\vec r - \vec r \,')}{|(\vec r - \vec r \,')|^3} $$
$$ \vec H = \ffd{1}{4 \pi} \int\! \ffd{\vec r - \vec r \,'}{|\vec r - \vec r \,'|^3} dq $$
$$ \vec H = \ffd{1}{4 \pi} \int\!\! \ffd{\vec r - \vec r \,'}{|\vec r - \vec r \,'|^3}\, dq $$
$$ a \times b = \sum_{i = 1}^a \sum_{j = 1}^b 1 = \sum_{j = 1}^b \sum_{i = 1}^a 1 = b \times a $$
$$ \sum_{i = 1}^a \sum_{j = 1}^b 1 $$
$$ \begin{array}{l} x^2 + 25x - 144 \\ =\left(x-\ffd{25-\sqrt{1201}}2\right)\left(x-\ffd{25+\sqrt{1201}}2\right) \end{array} $$

$$ abcdefghijklmnopqrstuvwxyz $$$$ abc dx dy $$

$$ \iro[ak]{c\tau} $$$$ \iro[ak]{ct} $$$$ \iro[ao]{vt} $$$$ \iro[ak]{(c\tau)^2} = \iro[ak]{(ct)^2} - \iro[ao]{(vt)^2} $$

$$ c\tau = \sqrt{c^2 - v^2}\sx t $$$$ \tau = \sqrt{1 - \ffd{v^2}{c^2}}\sx t $$

$$\underbrace{4+4+4+4+4+4}_{5.3} $$
$$\underbrace{\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{0.3\;\;}}_{5.3} $$
$$4\;\underbrace{\overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{0.3\;\;}}_{4.3} $$

$$ \iro[mr]{\theta} $$$$ \iro[mr]{\:b} $$$$ \iro[ao]{\:b_x} $$$$ \iro[ak]{\:b_y} $$$$ \iro[gy]{\:a} $$$$ \iro[mr]{\:b'} $$$$ \iro[ao]{\:b_x'} $$$$ \iro[ak]{\:b_y'} $$$$ \iro[gy]{\:a_x} $$$$ \iro[gy]{\:a_y} $$

$$ dh(t) = d(f(t)g(t)) = df(t)g(t) + f(t)dg(t) + df(t)dg(t) = df(t)g(t) + f(t)dg(t) $$
$$ df(t) = d\left(\ffd{h(t)}{g(t)}\right) = \ffd{dh(t)g(t) - h(t)dg(t)}{g(t)^2} $$
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Last-modified: 2021.0419 (月) 0351.5500 (1093d)