tmp のバックアップの現在との差分(No.4) |
#spanend &spanadd; \begin{array}{l}&spanend; &spanadd; x^2 + 25x - 144&spanend; &spanadd; \\ =\left(x-\ffd{25-\sqrt{1201}}2\right)\left(x-\ffd{25+\sqrt{1201}}2\right)&spanend; &spanadd; \end{array}&spanend; #spanadd #spanend #spanadd \underbrace{4+4+4+4+4+4}_{5.3} #spanend #spanadd #spanend #spanadd \underbrace{\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{1\;\;}+\overbrace{4}^{0.3\;\;}}_{5.3} #spanend #spanadd #spanend #spanadd 4\;\underbrace{\overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{1\;\;}\; \overbrace{\;+\;\;\,4\;}^{0.3\;\;}}_{4.3} #spanend #spanadd #spanend &spanadd; dh(t) = d(f(t)g(t)) = df(t)g(t) + f(t)dg(t) + df(t)dg(t) = df(t)g(t) + f(t)dg(t)&spanend; #spanadd #spanend &spanadd; df(t) = d\left(\ffd{h(t)}{g(t)}\right) = \ffd{dh(t)g(t) - h(t)dg(t)}{g(t)^2}&spanend; #spanadd |